Couple and kids problem
Suppose a couple have $4$ children and let's assume the probability of
having a boy is $0.6$. What is the probability that the fourth child is
the third boy?
So all boys are the "same", this gives us three possible combinations
BBGB GBBB BGBB
Would the answer simply be $3(0.6)^3(1-0.6)^{4-3}$?
No comments:
Post a Comment